3x^2-4x+14=9x^2-7x+19

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Solution for 3x^2-4x+14=9x^2-7x+19 equation: 



3x^2-4x+14=9x^2-7x+19

We move all terms to the left:

3x^2-4x+14-(9x^2-7x+19)=0

We get rid of parentheses

3x^2-9x^2-4x+7x-19+14=0

We add all the numbers together, and all the variables

-6x^2+3x-5=0

a = -6; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·(-6)·(-5)
Δ = -111
Delta is less than zero, so there is no solution for the equation

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